Question

A stone is tied to one end of a string and whirled in a horizontal circle of radius 1 m at 20 revolutions

per minute. Calculate the angular velocity and linear speed of the stone. Also find the centripetal

acceleration.​

Answer 1

Answer:

a=rω2;ω=2πv

22 revolution = 44 sec.

1 revolution = 44/22 = 2 sec.

u = 1/2 Hz

a=rω2=1×4π24=π2m/s2.

Towards the centre, the centripetal acceleration = - ω2 R

and away from the centre, the centrifugal acceleration is + ω2 R

∴ (a) and (b) are correct as the directions are given

Explanation:

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