a stone is trown vertically upward and direction with a velocity of 5m/s . if the acceleration of stone is 10m/s in downward direction .what will be hieght attain by stone and what time will it take to reach there
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The time for the particle to reach its maximum height will be
U= 5
Then
5/10 = 0.5 SECONDS
the maximum height will be
= 5(0.5)-5(0.5*0.5)
= 2.5-5(0.25)
= 2.5-1.25
=1.25 metres
U= 5
Then
5/10 = 0.5 SECONDS
the maximum height will be
= 5(0.5)-5(0.5*0.5)
= 2.5-5(0.25)
= 2.5-1.25
=1.25 metres
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