Question

a stone is vertically thrown upward and reaches at the height of 5m after 2sec.finds it's initial velocity ​

Answer 1

Explanation:

The equation is given as v 2 −u 2

=2as.

where,

v = final velocity,

u = initial velocity,

a = acceleration due to gravity, 10m/S2,

s = h = height traveled.

Therefore, we can find u with above info. In this case, v = 0 at the top of the path.

0−u2 =2×10×5=10m/s.

Hence, the initial velocity of the stone was 10 m/s.

Hope this helps you

Answer 2

Answer:

Given,

height=5m

time=2s

final velocity=0m/s

g=-10m/s²(you can also take -9.8m/s² and - sign indicates that it is decelerating and so the Final velocity becomes zero)

Now,

v²-u²=2gh

0²-u²=2*(-10)*5

-u²= -100

u=√100=10

So, initial velocity= 10m/s

please mark me as brainliest if it helped

have a great day:)