a stone of 1kg is thrown with a velocity of 20m/sec^1 across the frozen surface of a lake and comes to rest after traveling a distance of 50m. what is the force of friction between the stone and the ice
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Answered by
1
Answer:
4 N
Explanation:
use the method v square and u square/2×distance then you solve it then u will get answer then multiple with mass × solved answer
Answered by
2
Answer:
Best explanation be swagaat bhagat
Explanation:
See this and learn from me
- Go walk 20m don't see back
- then walk 59m but don't see back
- If you are a borring girl/boy then you don't understand
- byee
- say thnx to me
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