A stone of mass 0.05kg is thrown vertically upwards . what is the direction and magnitude of net force on the stone during the upward motion ?
Answers
Explanation:
0.5 N, in vertically downward direction, in all cases
Acceleration due to gravity, irrespective of the direction of motion of an object, always acts downward. The gravitational force is the only force that acts on the pebble in all three cases. Its magnitude is given by Newton's second law of motion as:
F = m x a
Where,
F = Net force
m= Mass of the pebble = 0.05 kg
a = g = 10 m/s2
∴F = 0.05 x 10 = 0.5 N
The net force on the pebble in all three cases is 0.5 N and this force acts in the downward direction.
If the pebble is thrown at an angle of 45° with the horizontal, it will have both the horizontal and vertical components of velocity. At the highest point, only the vertical component of velocity becomes zero. However, the pebble will have the horizontal component of velocity throughout its motion. This component of velocity produces no effect on the net force acting on the pebble.
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Answer:
F = m x a
Where,
F = Net force
m= Mass of the pebble = 0.05 kg
a = g = 10 m/s2
∴F = 0.05 x 10 = 0.5 N
The net force on the pebble in all three cases is 0.5 N and this force acts in the downward direction.
If the pebble is thrown at an angle of 45° with the horizontal, it will have both the horizontal and vertical components of velocity. At the highest point, only the vertical component of velocity becomes zero. However, the pebble will have the horizontal component of velocity throughout its motion. This component of velocity produces no effect on the net force acting on the pebble.