Question

A stone of mass 0.25 kg is whirled in a circle of radius 1.5m.What is the maximum speed with which the stone can be whirled around if the string can withstand tension of 600N.​

Answer 1

Question :-

A stone of mass 0.25kg is whirled in a circle of radius 1.5m.What is the maximum speed with which the stone can be whirled around if the string can withstand tension of 600N.

Answer :-

$\to \boxed{ \: \sf \: v_{max} =60 \: \frac{m}{ {s}^{2} } } \\ \\ \sf \: hence \: maximum \: velocity \: is \: 60 \: \frac{m}{ {s}^{2} } \:$

To Find :-

Maximum speed .

Solution :-

Given that :

• Mass of stone (m) = 0.25 kg

• radius of circle (r) = 1.5 m

• $\sf T_{max.} = 600 N$

We know that ,

if any Object is pure rotating so centripetal force is provided by tension in string .

We know that ,

let v be the speed of stone

$\to \boxed{\sf \: v_{max} = \sqrt{T_{max.} \times \frac{r}{m} } }$

Replace the given values in above formula :

$\to \: \sf \: v_{max} = \sqrt{600 \times \frac{1.5}{0.25} } \\ \\ \to \: \sf \: v_{max} = \sqrt{ \frac{ \cancel{600} \times 15 \times 10}{ \cancel{25}} } \\ \\ \to \: \sf \: v_{max} = \sqrt{ 24 \times 150} \\ \\ \to \: \sf \: v_{max} = \sqrt{3600} \\ \\ \to \boxed{ \: \sf \: v_{max} =60 \: \frac{m}{ {s}^{2} } } \\ \\ \sf \: hence \: maximum \: velocity \: is \: 60 \: \frac{m}{ {s}^{2} }$

Answer 2

Answer:

60 m/s^2 is the correct answer

Explanation: