Question

Three iron small cubes with sides 3cm 4cm and5cm respectively are melted and cast into big cube what is the ratio of total surface areas of sum of three cubes and abig cube ​

Answer 1

Surface area of 1st small cube = 3² x 6 = 54 cm²

Surface area of 2nd small cube = 4² x 6 = 96 cm²

Surface area of 3rd small cube = 5² x 6 = 125 cm²

[side of big cube]² = 3 x3 x 3 + 4 x 4 x 4 + 5 x 5 x 5

side of big cube= ³√216 = 6 cm

surface area of big cube = 216 cm

Sum of areas of the small cubes = 275 cm

Ratio = 275/216

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