Question

A stone of mass 0.4 kg is thrown vertically up with a speed of 9.8 m/sec square . find the potential energy after half second.

Answer 1

mass of stone is 0.4 kg

velocity is 9.8 m/sec (initial)

Time is half second

acceleration is -9.8 m/sec²

Finding the height of the stone after half second :-

$s = ut + \frac{1}{2}a {t}^{2} \\ \\ \\s = 4.9 - \frac{4.9}{4} \\ \\ \\ s = 4.9(1 - \frac{1}{4}) \\ \\s = \frac{4.9 \times 3}{4} \\ \\ \\s = 1.225 \times 3 \\ \\ s = 3.675 \: metres$

We know that

potential energy is equal to:-

$= mgh \\ \\ \\ = 0.4 \times 9.8 \times 3.675$

It is equal to 14.406 Joules

Answer 2

Answer:

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