A stone of mass 0.4 kg is thrown vertically upward with speed 9.8 m/s. Find the kinetic energy and potential energy after half second.
Answers
KE = 1/2 * m * v^2
KE = 1/2 * 0.4 * 9.8^2 = 19.208 J
PE = mgs
Assuming, the ball was thrown from 0 distance from surface,
s = 9.8 * 0.5 + 1/2 * -10 * 0.5^2 = 3.65 m
PE = 0.4 * 10 * 3.65 = 14.6 J
Please comment if you find anything odd, or have a doubt.
The kinetic energy and potential energy after half second will be 4.802 J and 14.406 J respectively.
Explanation:
Given:
A stone of mass 0.4 kg is thrown vertically upward with speed 9.8 m/s.
To Find:
The kinetic energy and potential energy after half second.
Solution:
As given,a stone of mass 0.4 kg is thrown vertically upward with speed 9.8 m/s.
Mass of a stone m = 0.4 kg
Speed u =9.8 m/s.
t=0.5 second
a= -g
Speed of stone after half second
The kinetic energy
After half second stone height will be
The potential energy
Thus,the kinetic energy and potential energy after half second will be 4.802 J and 14.406 J respectively.
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