Question

a stone of mass 0.5 kg tied with a string of length one metre is moving in a horizontal circular path with a speed of 4 metre per second tension acting on the string in newton is

Answer 1

The centripetal force for the stone is equal to the tension T in the string

Answer 2

Hey there,

◆ Answer-
T = 8 N

◆ Explaination-
# Given-
m = 0.5 kg
v = 4 m/s
r = 1 m

# Solution-
In horizontal circular motion, tension in the string is provided by centripetal force.
T = mv^2 / r
T = 0.5 × (4)^2 / 1
T = 8 N

Therefore, tension in the string during this motion is 8 N.

Hope this helps ...