Physics, asked by haileybates16, 1 year ago

A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8 joules at the point of impact with the ground. What is the stone's velocity when it hits the ground?

Answers

Answered by AnonymousKSB

0

Explanation:

kinetic energy=1/2mv^2

9.8=1/2×.55×v^2,v=velocity

velocity=5.96 m/s

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