Question

A stone of mass 10 g is being moved in a circle of
radius 50 cm with a uniform speed of 1 m/s. The
acceleration of the stone is​

Answer 1

Step-by-step explanation:

f=(centripetal force )

v is the tangential velocity

r is the radius of circle

r = 50cm = 0-5cm

v=1m^51

f=ma =mv^2 r^-2

a=v^2 r^-2

therefore

centripetal acceleration

= (1)^/(0-5)=2m5^2

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