A stone of mass 100Kg is dropped on to a heap of sand with a velocity of 20m/s.The stone penetrates into the sand and stops in 0.05s.Find the force applied by the sand stone.
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Answer:
your answer is below buddy okk..
Explanation:
firstly---
we know that F=m*a(Force=mass *acceleration)
mass is given 100kg,so we find acceleration now.
a=v-u/t
a=20-0/0.05(here we take u=0 because before the falling of stone the stone's initial velocity (u) is zero)
a=400m/s^2
F=m*a
F=100kg*400m/s^2
F=40,000N
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