Question

A stone of mass 2 kg is falling from rest from the top of state known what will be its kinetic energy after 2 seconds g equals to 10 M 5 - 2

Answer 1

v=u+at

v=0+10×2

v=20m/s

so KE=1/2mv^2

=1/2 ×2×(20)^2

=20×20

=400 joule

Answer 2

k.e=1/2 mv²
v=u+gt
u=0
v=10×2
v=20m/sec..
K.E=1/2×2×400
K.E=400joule