a stone of mass 2 kg is falling from the from rest from the top of Steel Hill what will be its kinetic energy after 5 seconds
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Answered by
8
Mass = 2 kg
Initial velocity = 0 m/s
Time =5 sec
Therefore final velocity =u + at
V = 0+ 10*5
V = 50 m/s
Therefore kinetic energy = ½ mv²
K.E. = 1/2-*2*50*50
K.E = 2500 J
I hope it helps……..
Initial velocity = 0 m/s
Time =5 sec
Therefore final velocity =u + at
V = 0+ 10*5
V = 50 m/s
Therefore kinetic energy = ½ mv²
K.E. = 1/2-*2*50*50
K.E = 2500 J
I hope it helps……..
sparsh28:
if g=10ms
Answered by
0
mass is 2kg
u=0
please see the below image for more understanding
u=0
please see the below image for more understanding
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