A stone of mass 2kg is attached to a string 3m long and is whirled in a horizontal circle. The string can withstand a maximum tension 2.5 kg wt. Calculate maximum velocity of revolution that can be given to the stone without breaking the string.
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Opposing the tension will be the centrifugal force of magnitude =MV²/R
Here M=2kg R=3m
Therefore Max centrifugal force =Max tension
MV²/R=2.5
V=(2.5*R/M)½
V=(2.5*3/2)½
V=(7.5/2)½
V=(3.75)½
V=1.936m/s
And angular velocity =1.936*3=5.809/s
Here M=2kg R=3m
Therefore Max centrifugal force =Max tension
MV²/R=2.5
V=(2.5*R/M)½
V=(2.5*3/2)½
V=(7.5/2)½
V=(3.75)½
V=1.936m/s
And angular velocity =1.936*3=5.809/s
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