Question

A stone of mass 2kg is dropped from the top of a tower of height 40m what will be its K.E 10m below the top​

Answer 1

$\longrightarrow$ Assuming that there is no air resistance (no heat energy produced) then the loss in gravitational potential energy (mgh) equals the gain in kinetic energy.

$\longrightarrow$ The kinetic energy at the top is zero (as there is no motion).

$\longrightarrow$ So,

• kinetic energy after falling 10 metres = m g h

Where,

m = mass = 2kg

g = gravitational acceleration = 9.81

h = 10

• = 2 x 9.81 x 10

• $\sf = 2 × \frac{98.1}{10} × 10$

• $\sf = 2 × \frac{98.1}{\cancel{10}} × \cancel{ 10}$

• = 196.2 J

I hope it helps you ❤️✔️

Answer 2

Answer:

The answer is $196.2 J$

Explanation:

Kinetic energy is a type of power that a moving object or particle possesses. When work, which entails the transfer of energy is performed on an object by applying a net force, that object acquires kinetic energy. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion. The type of motion can be vibrating, revolution on an axis, translations (or travel along a route from one point to the other), or any mixture of these.

The energy that an object has as a result of motion is known as kinetic energy. It is, in essence, the energy of a moving body. Kinetic energy is a vector value, meaning that it only supplies the quantity and not the directions of an event. It cannot be negative.

Following a 10 meter fall, kinetic energy remains $=mgh$

$mass(m) = 2kg$

$g = gravitational acceleration = 9.81$

$h = 10$

  $= 2*9.81*10$

  $=2*\frac{98.1}{10} *10$

  $= 196.2 J$

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