Question

a stone of mass 4 kg is released from the tower of height 120 follow freely to the ground find out the time taken by the stone to reach the ground(assume valum of g=10m/s2)​

Answer 1

Answer:

Time taken = 2 * [6^(1/2)] seconds. or

Time taken = 2 root 6 seconds.

Explanation:

h = 120 m (height of the building)

g = 10 m/s^2 (given)

u = 0 m/s (the object was at rest)

Using the 2nd equation of motion, h = u(t) + 1/2(g)(t^2)

120 = 0(t) + 1/2(10)(t^2)

it implies, 120 = 0 + 5(t^2)

it implies, 120 = 5(t^2)

it implies, 24 = t^2

it implies, 24^(1/2) = t

it implies t = 2 * [6^(1/2)] seconds or

t = 2 root 6 seconds.

Therefore, time taken = 2*[6^(1/2)] seconds or 2 root 6 seconds.

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