Question

a stone of mass 50 gram is been rotated in the circle of radius 15 cm with a uniform speed of 2 metre per second what is the acceleration of the stone​

Answer 1

Answer:

acceleration [a]=4.25 m/s²

Explanation:

initially the stone would be at rest

thus,

initial velocity[u]=0 m/s

final velocity[v]=2 m/s

radius=15 cm=0.15 m

distance traveled by the stone=circumference of the circle

circumference=2πr

=2*3.14*0.15

=0.3*3.14

=0.94 m

speed=distance/time

2 m/s=0.94 m/time

time=0.94/2

time=0.47 seconds

v=u+at

2=0+a[0.47]

2=0.47a

a=2/0.47

a=4.25 m/s²