Question

a stone of mass 6kg is revolved in a verticle circle of t diameter 6m, such that its speed at a point is minimum at that pointn.if the K.E at the same point is 250J , then minimum P.E a that point is​

Answer 1

Answer:

200J

Explanation:

K.E=250

T.E=5mgr/2=450

P.E=450-250=200