A stone of mass 750g is thrown vertically upwards with a velocity of 10m/s. Calculate the potential energy at the greatest height.
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Answer:
37.485J (joules)
Explanation:
Given:
mass(m) = 750g = (750/1000)kg = 3/4 kg
initial velocity(u) = 10m/s
At greatest height(s), the velocity of the body will be 0
=> final velocity(v) = 0m/s
Potential energy(P.E) = m*gravitational acceleration(g)*s
We need to find the value of height(s) so that we have the value of every variable in the P. E formula.
According to the third equation of motion;
v^2 - u^2 = 2*acceleration(a)*s
a = g in this case as acceleration produced is due to acceleration due to gravity on the body.
=> a = -9.8 m/s^2 minus as the ball is thrown vertically upwards so acceleration is in the opposite direction of that of gravity.
=> 0 - (10)^2 = 2*(-9.8)*s
=> -100 = 2*( -19.6)*s
=> s = 5.10m
Now,
P.E = (3/4)*(9.8)*(5.10)
=> P.E = (149.94)/(4)
= 37.485J
Hence,
P.E at greatest height reached by the body is 37.485J
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