Question

A stone of weight 100 gf and volume 35 cm[tex]^{2} [)tex] immersed in water. What is the apparent weight of stone in water ?​

Answer 1

$\underline{Correct\:Question:}$

A stone of weight 100 gf and volume 35 cm$^{2}$ immersed in water. What is the apparent weight of stone in water ?

$\underline{Solution:}$

$\underbrace{Weight \: of \: stone \:is \: 100 \: gf}_{given}$

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⠀and

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$\underbrace{volume \: of \: stone \: is \: 35 \:cube \:cm}_{given}$

We have to find apparent weight of stone when it is immersed in water.

Volume of stone is 35cm$^{3}$ and volume of water displaced = (V) = 35cm$^{3}$

Density of water (d) = 1 cm$^{–3}$

$\therefore$ Mass of water displaced = V × d = 35 (cm$^{–3}$) = 35 g

$\therefore$ Weight of water displaced = 35 gf.

$\mathbb {Now \: by \: Archimedes' \: Principle}$

Upthrust = Weight of fluid (water) displaced = 35 gf

$\therefore$ Apparent weight of stone in water = (100 – 35) gf

= 65 gf.