Question

A stone on the edge of vertical Cliff is kicked so that its initial velocity is 9 m/s horizontally. If the Cliff is 200m high calculate time taken by stone to reach the ground and how far from the Cliff the stone will hit the ground

Answer 1

Answer:

t=2root10

r=18root10

Explanation:

use time and range formula of oblique projectile

Answer 2

Time taken by stone to reach the ground is 6.32 s.

The distance covered by the stone to hit the ground is 56.88 m

Explanation:

Initial horizontal velocity of the stone is 9 m/s.

The height of the cliff is 200 m.

Let t is the time taken by the stone to reach the ground. The initial vertical velocity of stone is 0. Using equation of motion to find time in vertical direction. So,

$h=ut+\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 200}{10}} \\\\t=6.32\ s$

The distance covered by the stone to hit the ground is :

d = v × t

$d=9\times 6.32\\\\d=56.88\ m$

Learn more,

Kinematics

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