a stone projected vertically up from the top of the tower with velocity of 19.6m/s aches it's foot in 6sec . find the height of the tower and the velocity with the stone reaches the ground
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3
Answer:
29.4m
Explanation:
From second equation of motion, s=ut+at
2
/2
Assume upward direction to be positive.
u=4.9 m/s, t=3 sec, a=−9.8 m/s
2
s=4.9×3−9.8×3
2
/2
s=−29.4 m
Height = 29.4 m
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