A stone released from the top of a tower of height 19.6 m calculate its final velocity just before touching the ground. (take g = 9.8 m/s2
Answers
Answered by
10
v^2 = u^2 + 2 a s
v^2 = 0 + 2 x 9.8 x 19.6
v^2 = 384.16
v = 19.6 ms^-1
v^2 = 0 + 2 x 9.8 x 19.6
v^2 = 384.16
v = 19.6 ms^-1
Similar questions