a stone suspended at the 20cm mark is balanced by a 100g mass suspended on the 60cm mark. assume g=10m/s.calculate the mass of the stone
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As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.
Here moment of forces are equal that is balance each other.
Hence m×(40−20)=100×(50−40)
⇒m=100/2=50g.
Hence value of m is 50g.
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