Question

A stone thrown down with a speed u takes a time t1 to reach the ground. while another stone thrown upward from the same point with the same speed, takes time t2. the maximum height the second stone reaches from the ground is

Answer 1

first find the height of projection which is 1/2gt1t2 boe find how much height the second particle goes which comes out by two equations

t2-t1 =2u/g-------1

hieght gain by second particle(h) = u^/2g -------2

by this you will find h is (t2-t1)^2/8g

now add both the heights to get the height gained by the particle