Physics, asked by Nira9583, 1 year ago

A stone thrown up is caught by the thrower after 6 second. How height did it go and where was it 4 seconds after did it start. ( Take g = 9.8 m /sec)

Answers

Answered by PrÃkHäRisprestigious
8
Using the formula mgh
6 X 9.8 = 58.6 m (height)
at 4 seconds it was on stable position nor upwards neither downwards
Mark as brillianist
Answered by allanpaul9112006
0

Explanation:

please mark it as brainlest

Attachments:
Similar questions