Question

a stone thrown upward with a speed u from the top of the tower reaches ground with a velocity 3u.The height of the tower is

Answer 1

Even if it is thrown from top of the tower the displacement is height of the tower. So use s=ut+1/2at^2.
Solution is in the attachment.

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Answer 2

S = (v^2 - u^2) / (2a)

H = ((3u)^2 - u^2) / (2g)

= (9u^2 - u^2) /(2g)

= 8u^2 / (2g)

= 4u^2 / g

Height of the tower is 4u^2 / g