Question

A stone thrown upwards attains a maximum height of 19.6 m. Find the velocity with which it was thrown.

Answer 1

H max=19.6m
g=9.8m/s²
u=?
we know that ,
v²-u²=2as
In vertically projected body ,s=h,v=0,a=-g
so,0²-u²=2×-9.8×19.6
-u²=-384.16
u²=384.16
u=✓384.16
u=19.6m/s

I hope it helps durga pal singh
Thanks for this question.

Answer 2

Given

H =19.6

u= ?

v =0

a = -g

Now,

v²-u²=2as

-u²=-2gH

u²=2gh

u=√2gh

=√2*9.8*19.6

=√19.6*19.6

=19.6m/s