Question

A stone thrown upwards attains a maximum height of 39.2 m. Find the velocity with which it was
thrown.​

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Distance covered by freely falling stone at  any instant

$t = \frac{1}{2} {gt}^{2}$

Distance covered by upward thrown stone 19.6t−$\dfrac{1}{2} {gt}^{2}$

If  they meet, sum=height of tower

$\dfrac{1}{2} {gt}^{2} and \: 19.6t - \dfrac{1}{2} {gt}^{2} = 39.9$

$19.6t = 39.2$

$t = 2s$

And they would meet at height of $19.6t \: \dfrac{1}{2} {gt}^{2}$

=39.2−19.6

=19.6m

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