Question

solve the equation x upon 2-3 = -5​

Answer 1

Answer:

First multiply out the bracket on the LHS of the equation.

3x3+18=2x2+27x

Rearrange to get a cubic equation.

3x3+18−2x2−27x=0

3x3−2x2−27x+18=0

Now find a number that can be substituted into x that will make the equation equal zero.

When x = 3, the equation is zero.

We now have a factor and now we can factorise the equation.

(x−3)(3x2+7x−6)→(x−3)(3x−2)(x+3)

Now you can find the answers for x.

x=3,−3,23

Answer 2

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solve the equation x upon 2-3 = -5

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > \frac{x}{2} - 3 = - 5$

=>L.C.M of x/2 and -3 is 2

$= > \frac{x - 6}{2} = - 5$

=>In the left side 2 is divided so when it goes to R.H.S its signs gets changed from divide to multiply.

$= > x - 6 = - 10$

$= > x = - 10 + 6$

$\bold{\red{= > x = - 4}}$

Now check the equation whether the X's value satisfies the equation or not :

$= > \frac{x}{2} - 3 = 5$

$= > - \frac{4}{2} - 3 = - 5$

$= > - 2 - 3 = - 5$

X's value satisfies the equation.

Hence,Value of x is -4

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