Question

a stone thrown vertically up with a velocity 50m/s. calculate maximum height reached stone and time taken reach of this height ?(a= -10m/s2​

Answer 1

Answer

• Time = 5 sec
• Height = 125m

Solution

• Initial velocity, (u) = 50m/s
• Final velocity, (v) = 0 (as it stopped at a point when we thrown upward)
• Acceleration, (g) = - 10m/s² (given)

We need to find maximum height reached stone

• Apply formula

→ v² = u² + 2gh

→ (0)² = (50)² + 2 × (-10) × h

→ 0 = 2500 - 20h

→ 20h = 2500

→ h = 2500/20

→ h = 125 m

• Height = 125m

Now need to find out time taken by stone to reach maximum height

• Again apply formula

→ v = u + gt

→ 0 = 50 + (-10) × t

→ 50 = 10t

→ t = 50/10

→ t = 5 sec

• Time = 5 sec

Answer 2

Answer:

Given :- u=50m\s

v=0

g=10m\s-2

h=?

t=?

Explanation:

v^2=u^2-2gh

(0)^2=(50)^2×10h

0=2500+20h

20h=2500

h=2500/20

h=125m (your first ans.)

v=u+gt

0=50+10t

10t=50

t=50/10

t=5sec (your second ans.)