A stone thrown vertically upward with a speed of 5 m/s attain a height of y1 another stone thrown upward from the same point with velocity of 10m/s attain a height y2. the correct relation between y1and y2
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For first stone
height=y1
u=5m/s
v²=u²-2gy1
0=25-20y1
y1=25/20=5/4
For second stone
height=y2
u=10m/s
v²=u²-2gy2
0=100-20y2
y2=100/20=5
y1/y2 = (5/4)÷5 = 1/4
y1= y2÷4
Therefore,
y2=4×y1
This is the correct relation between y1 and y2
Please mark as brainliest if you understand :-)
height=y1
u=5m/s
v²=u²-2gy1
0=25-20y1
y1=25/20=5/4
For second stone
height=y2
u=10m/s
v²=u²-2gy2
0=100-20y2
y2=100/20=5
y1/y2 = (5/4)÷5 = 1/4
y1= y2÷4
Therefore,
y2=4×y1
This is the correct relation between y1 and y2
Please mark as brainliest if you understand :-)
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