A stone thrown vertically upward with initial velocity u reaches a height h before comi down show that the time taken to go up is same as the time taken to come down
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consider upwards direction to be positive
for stone to go up;
initial velocity=u
height=h m
final velocity =0 m/s(at max. height v=0)
a=-10 m/s^2
v=u+at
0=u+(-10)t
u=10t
t=u/10 s
for stone going downwards,
initial velocity=-u m/s
a=10m/s^2
v=0 m/s
v=u+at
0=-u+10t
t=u/10 s
for stone to go up;
initial velocity=u
height=h m
final velocity =0 m/s(at max. height v=0)
a=-10 m/s^2
v=u+at
0=u+(-10)t
u=10t
t=u/10 s
for stone going downwards,
initial velocity=-u m/s
a=10m/s^2
v=0 m/s
v=u+at
0=-u+10t
t=u/10 s
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