A stone thrown vertically upwards take 3second to obtain maximum height. calculate the initial of the stone? find answers
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we know that time taken to reach maximum height .
t= usin theta/g
here theta = 90° so sin 90°=1
now 3=u/g
if we take g=10m/s^2
u=30m/s
t= usin theta/g
here theta = 90° so sin 90°=1
now 3=u/g
if we take g=10m/s^2
u=30m/s
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