. A stone thrown vertically upwards with a speed of 5 m/s. How much high the stone goes
before back to the earth? A=-9.8m/s2
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Answered by
3
v^2=u^2 +2as
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx
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Answered by
2
v^2=u^2 +2as
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx
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