Physics, asked by sabrina789, 1 year ago

. A stone thrown vertically upwards with a speed of 5 m/s. How much high the stone goes

before back to the earth? A=-9.8m/s2

Answers

Answered by Anonymous
3
v^2=u^2 +2as
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx

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Answered by Anonymous
2
v^2=u^2 +2as
0=25- 2×9.8 ×s
19.6s=25
s=25/19.6
s=1.27 m approx
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