Question

A stone thrown vertically upwards with
initial velocity u reaches a height ‘h
before coming down. Show that the
time taken to go up is same as the time
taken to come down.
​

Answer 1

Answer:

A stone thrown vertically upwards with initial velocity u reaches a height 'h' before coming down. ... when the stone reaches the maximum height after time t , its final velocity is zero. When the stone travelling vertically upwards, it is experiencing the retardation due to gravity.

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Answer 2

h is the maximum reached height, so the final velocity at that point is 0.

as v=u-gt

→0=u-gt

→u=gt

so,t=$\frac{u}{g}$.

when it comes down its initial velocity=0

so final velocity v=0 +gt

this implies that t=$\frac{v}{g}$.