Question

Verify whether ×=1 and X=1 arezero of the polynomial p(X) =(x²=1)​

Answer 1

Answer:

$p(x) = {x}^{2} - 1 \\ p(1) = {(1)}^{2} - 1 = 1 - 1= 0 \\ p( - 1) = {( - 1)}^{2} - 1 = 1 - 1 = 0$

Therefore, x=1 and x=-1 are the zeros of the polynomial p(x)

$hence, \: ( {x}^{2} - 1) = (x + 1)(x - 1)$