a stone thrown vertically upwards with initial velocity u reaches a height 'h' before coming down. show that the Time taken to go up is same as the time taken to come down.
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Answer:
Explanation:
When stone throw upward with initial velocity, u
Final velocity at maximum height, v=0
Apply kinematic equation of motion.
v=u+at
t=
a
v−u
=
−g
0−u
Apply kinematic equation of motion.
s=ut+
2
1
at
2
h=u(
g
u
)−
2
1
g(
g
u
)
2
u=
2gh
Time,
t=
g
u
=
g
2gh
t=
g
2h
.(1)
(ii) When stone drop from height h
Apply kinematic equation of motion.
v
2
−u
2
=2gh
v= u +at
2gh
Apply kinematic equation of motion.
v= t
t=
a
v−u
=
g
2gh
−0
=
g
2h
(2)
From (1 ) and (2) it is proved that the time taken to go up is same as the time taken to come down.
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