A stone thrown vertically upwards with initial velocity u reached a height h before coming down. Show that the time taken to go up in same as the time taken to came down.
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when the ball is in your hand it's U is 0 when u throw it it catches some speed that is v1 then at a certain point is came back, on its certain point it became again 0 and returned with some speed v2 ; now our first v1 is U and second is v2 is V the result will be 0 if their distance is equal
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