Question

A stone tied to an end of a string 40cm long is whirled in a circle at a constant speed. If the stone makes 28 revolutions in 20 seconds, calculate the magnitude of its linear velocity.

Answer 1

The magnitude of its linear velocity of the stone is 3.51 m/s

Explanation:

Given that,

Length of the string, r = 40 cm = 0.4 m

The stone makes 28 revolutions in 20 seconds. The angular velocity of the stone is given by :

$\omega=\dfrac{28\ rev}{20\ s}\\\\\omega=1.4\ rev/s\\\\\omega=8.79\ rad/s$

The relation between the linear and angular velocity is given by :

$v=r\omega$

$v=0.4\ m\times 8.79\ rad/s\\\\v=3.51\ m/s$

So, the magnitude of its linear velocity of the stone is 3.51 m/s. Hence, this is the required solution.

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Angular velocity

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Answer 2

Explanation:

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