Question

A stone tied to end of a string 80 cm long is whirled in a horizontal with a constant speed. If the stone makes 14 revolutions in 25seconds, what is the magnitude and direction of acceleration of the stone ?

Answer 1

Answer:

Frequency f=

25

14

Hz

Angular velocity ω=2πf=

25

2×14π

rad/s=3.52rad/s

Acceleration is a=ω

2

r=3.52

2

×0.8=9.9m/s

2

The direction is along the radius at every point towards the centre.