a stone tied to the end of a string 80cm long is whirled in a horizontal circle with a constant speed if the stone makes 14 revolution in 25 seconds what is the magnitude of acceleration of the stone
Answers
Answered by
0
Answer:same as other guy said...
Explanation:
Answered by
0
Answer:
Acceleration of the stone is 9.91 m/s² and direction along the radius towards the Centre.
Explanation:
r = 80 cm = 0.8 m
f = 14/25 = 0.56
ω = 2πf = 2π ×0.56 = 3.52
= rω² = 0.8×(3.52)² = 9.91 m/s²
= centripetal acceleration ⇒ along the radius towards the Centre.
Similar questions