Question

A stone tied to the end of a string of length 50 cm is whirled in a horizontal circle with a constant speed. If the stone makes 40 revolution in 20 seconds then the speed of the stone along the circle is??

Answer 1

Answer:

Explanation:

» Radius = r = 50 cm = 0.5 m

» In 20 sec revolution = 40

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» in 1 sec revolution = 40/20 = 2 Hz

» N = 2 Hz

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Now

» Angular Velocity = w = 2πn

» Angular Velocity = w = 2×3.14×2

» Angular Velocity = w = 12.56

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» Radial Acceleration = w²r

» Radial Acceleration = (12.56)²×0.5 m/s²

» Radial Acceleration =  78.8768m/s²

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