Question

A stone weighs 20g in air. 15g in water, find the relative density of the stone.

Answer 1

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$<b><u>Answer</u></b>$

$<b>Relative density of the stone is 4.</b>$

$<b><u>Step-by-step explanation</u></b>$

$<b>Given conditions =></b>$

Weight of stone in air $(W_{1})$ = 20g

Weight of stone in water $(W_{1})$ = 15g

$<b>To find,</b>$

$<b>Relative Density = ? </b>$

∴ Therefore, apparent loss in weight = $(W_{1} - W_{2})$ g

= 20g - 15g

= 5g

Relative density = $\frac{W}{(W_{1} - W_{2})}$

Relative density = $\frac{20g}{5g}$

Relative density = 4

$<b>∴ Therefore, the relative density of the stone is 4.</b>$

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