Math, asked by BrainlyHelper, 1 year ago

Solve the following quadratic equations by factorization: 9x²-6b²x-a⁴-b⁴=0

Answers

Answered by nikitasingh79
8

SOLUTION :  

Given : 9x² - 6b²x - (a⁴ - b⁴)  = 0

9x² - 6b²x - ((a²)² - (b²)²)  = 0

9x² - 6b²x - (a² - b²) (a² + b²) = 0

9x²  + 3 (a² - b²)x - 3 (a² + b²)x - (a² - b²) (a² + b²) = 0

[3(a² - b²) ×  3 (a² + b²) = 9(a⁴ - b⁴ )  &  3 (a² - b²) - 3 (a² + b²) = - 6b²]

3x [3x(a² - b²)]   - (a² + b²) [3x + (a² - b²) ] = 0

[3x + (a² - b²) ]  [3x - (a² + b²) ] = 0

[3x + (a² - b²) ]  = 0  or     [3x - (a² + b²) ] = 0

3x = - (a² - b²)  or  3x =  (a² + b²)

x = [ - (a² - b²)/3]   or  x = [(a² + b²)/3]

x = (b² - a²)/3  or  x = [(a² + b²)/3]

Hence, the roots of the quadratic equation 9x² - 6b²x - (a⁴ - b⁴)  = 0  are (b² - a²)/3 &  [(a² + b²)/3] .

★★ METHOD TO FIND SOLUTION OF a quadratic equation by FACTORIZATION METHOD :  

We first write the given quadratic polynomial as product of two linear factors by splitting the middle term and then equate each factor to zero to get desired roots of given quadratic equation.

HOPE THIS ANSWER WILL HELP YOU….

Answered by Anonymous
22

Answer :

The roots of the quadratic equation 9x² - 6b²x - (a⁴ - b⁴)  = 0  are (b² - a²)/3 &  [(a² + b²)/3] .

Step-by-step explanation :

Given - 9x² - 6b²x - (a⁴ - b⁴)  = 0

⇒ 9x² - 6b²x - ((a²)² - (b²)²)  = 0

⇒ 9x² - 6b²x - (a² - b²) (a² + b²) = 0

⇒ 9x²  + 3 (a² - b²)x - 3 (a² + b²)x - (a² - b²) (a² + b²) = 0

⇒ [3(a² - b²) ×  3 (a² + b²) = 9(a⁴ - b⁴ )  &  3 (a² - b²) - 3 (a² + b²) = - 6b²]

⇒ 3x [3x(a² - b²)]   - (a² + b²) [3x + (a² - b²) ] = 0

⇒ [3x + (a² - b²) ]  [3x - (a² + b²) ] = 0

⇒ [3x + (a² - b²) ]  = 0  or     [3x - (a² + b²) ] = 0

⇒ 3x = - (a² - b²)  or  3x =  (a² + b²)

⇒ x = [ - (a² - b²)/3]   or  x = [(a² + b²)/3]

How to solve quadratic equations by factorization :

At first write the given quadratic polynomial as product of the two linear factors by splitting it's middle term.

Then equate both factor equivalent to zero to get the roots of given quadratic equation.


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