a stone with weight w is thrown vertically upward into the air from ground level with initial speed vo if a force due to air drag acts on the stone throughout its flight the maximum height attained by stone
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Force due to air drag bot given
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Answer:
Explanation:
According to the problem the weight of the stone is w
therefore the mass will be m = w/g
As we know the air drops any particle in the opposite direction of its velocity therefore for this case,
w/g x a = w - f
here a is the acceleration of the stone with its velocity towards up
=> a = (w-f) x g/w
Let the maximum height attained is h
Now from equation of motion we can say that,
0 = v0^2 - 2ah
h = v0^2/2a
= v0^2/ 2 (w-f) x g/w
= wv0^2/2(w−f) x g
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