Question

a storage oil tanker consists of a cylindrical portion 7 m in diameter with 2 hemispherical ends of the same diameter . the total length of the tanker is 20m and it is lying horizontally . if itcontainsoil to a depth of 3.5 m , find the amount of oil in it

Answer 1

If the tank has oil to the depth of 3.5m this shows oil is in two half hemispherical end as well as in half cylinder radius of hemisphere = 3.5m so you have to calculate volume of a hemisphere and half cylinder. 

So volume of oil in the tank = volume of hemisphere + volume of half of cylinder 

So the volume of oil will be equal to 2/3π$2/3 \pi r^{3} = 2/3 * 22/7 (3.5)3 = 89.833 m^{3}$

Height of cylinder = total length of tank – 7m = 20-7 = 13m 

And volume of half cylinder = $1/2 \pi r^{2} h = 1/2 * 22/7 * 49/4 * 13 = 250.25 m^{3}$

So total amount of water = 89.83 + 250.25 = $340.08 m^{3}$