Question

A store is selling a jacket on sale at 30% off the marked price. a matching pair of pants is on sale at 50% off the marked price. if the marked price of the pants is rs. 11600 less than the marked price of the jacket and the total sale price of both items is rs. 14600, then what is the marked price of the jacket?

Answer 1

Let the C.P of the jacket be 'x'

Let the C.P of the pants be 'y'

S.P of the jacket = C.P of the jacket - Discount on the jacket

= x - 30x/100

= 70x/100

= 0.7x

S.P of the pants = C.P of the jacket - Discount of the pants

= y - 50x/100

= 50x/100

= 0.5y

C.P of pants is less than Rs.11600 less than C.P of jacket

i.e y = x - 11600 ----------------(1)

S.P of two items is Rs.14600

i.e 0.5y + 0.7x = 14600

Substitute the value of y which is obtained in (1)

=> 0.5 (x - 11600) + 0.7x = 14600

=> 0.5x + 0.7x - 5800 = 14600

=> 1.2x - 5800 = 14600

=> 1.2x = 14600 + 5800

=> 1.2x = 20400

=> x = 17000

The marked price of jacket is Rs.17000

Hope it helps.

Answer 2

Let the marked price (M.P) of the jacket = 'x’ &

marked price (M.P) of the pants = 'y'

Discount on the jacket= 30%of M.P= 30x/100

S.P of the jacket = M.P of the jacket - Discount on the jacket

= x - 30x/100

= 70x/100

= 7x/10

= 0.7x


Discount on the Pants = 50%of M.P= 50y/100

S.P of the pants = M.P of the jacket - Discount of the pants

= y - 50y/100

= (100y -50y)/100

= 50y/100

= 5y/10

= 0.5y



M.P of pants is less than Rs.11600 less than M.P of jacket। ( given)

y = x - 11600 ……………… (1)

Total S.P of both items = ₹14600 (given)

S.P of jackets + S P of pants = 14600

0.5y + 0.7x = 14600


Put the value of y from eq (1)

0.5 (x - 11600) + 0.7x = 14600

0.5x - 5800 +0.7x = 14600

0.5x + 0.7x - 5800 = 14600

1.2x - 5800 = 14600

1.2x = 14600 + 5800

1.2x = 20400

x= 20400/1.2= 204000/12

x = 17000

Hence, the marked price of jacket is ₹17000.

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Hope this will help you...